Tourney TDA Premature Flop (29 Viewers)

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Howdy friends

B: A premature turn card: leave the turn burn card as the burn. Return the premature turn card to the deck stub and reshuffle the entire stub. Re-deal the turn (without another burn) from the newly shuffled stub

If a premature flop occured and it is resolved, but then afterward the dealer accidentally burned a card instead of redealing the turn without a burn, is it as simple as reshuffling the burned card and the *TURN* card back and dealing another *TURN*, or is that burned card now the river burn and the *TURN* card stands? No action on the *TURN* has occured.

I let the *TURNED* card stand and the incorrect burn card be the river burn, but now I am inclined to put both the burn card and the dealt *TURN* back in the deck to redeal another card without a burn for the *TURN*, since a burn card for the *TURN* is 'already in the chamber' from the first premature flop mistake.
 
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i think i get what you are trying to ask, but are you using flop and turn interchangeably?

assuming so, and assuming there was no action on the turn yet, the mistakenly burned card becomes the turn, and the card that was wrongly dealt as the turn goes back on top of the stub, where it will naturally end up as the (exposed) river burn card.

the goal is to put every card where it would have been without the error, and you can actually just ignore the original error - this is how you would handle if the dealer accidentally burned twice.
 
i think i get what you are trying to ask, but are you using flop and turn interchangeably?

assuming so, and assuming there was no action on the turn yet, the mistakenly burned card becomes the turn, and the card that was wrongly dealt as the turn goes back on top of the stub, where it will naturally end up as the (exposed) river burn card.

the goal is to put every card where it would have been without the error, and you can actually just ignore the original error - this is how you would handle if the dealer accidentally burned twice.
Hey Raynmanas, thanks for pointing it out. I updated the wording, you were right I did not communicate properly the issue.

If there is already a turn burn card, and another card is burned, and another card exposed on the turn, the 2nd burned card becomes the turn and the revealed card goes back in the deck to be shuffled?
 
Hey Raynmanas, thanks for pointing it out. I updated the wording, you were right I did not communicate properly the issue.

If there is already a turn burn card, and another card is burned, and another card exposed on the turn, the 2nd burned card becomes the turn and the revealed card goes back in the deck to be shuffled?

no, the revealed card becomes the river burn, so the same river comes out. then you have the "correct" turn and river card, and there is no need to shuffle again. everyone just shares the knowledge of that exposed card now.
 
Howdy friends

B: A premature turn card: leave the turn burn card as the burn. Return the premature turn card to the deck stub and reshuffle the entire stub. Re-deal the turn (without another burn) from the newly shuffled stub

If a premature flop occured and it is resolved, but then afterward the dealer accidentally burned a card instead of redealing the turn without a burn, is it as simple as reshuffling the burned card and the *TURN* card back and dealing another *TURN*, or is that burned card now the river burn and the *TURN* card stands? No action on the *TURN* has occured.

I let the *TURNED* card stand and the incorrect burn card be the river burn, but now I am inclined to put both the burn card and the dealt *TURN* back in the deck to redeal another card without a burn for the *TURN*, since a burn card for the *TURN* is 'already in the chamber' from the first premature flop mistake.
This is called the Harris conundrum
 

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